Electrolysis and Storage Batteries MCQs
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Secondary cell large amounts of power for a
- A. short time and can be recharged
- B. long time and can be recharged
- C. short time and cannot be recharged
- D. long time and cannot be recharged
- Correct Answer: Option A
Nickel-cadmium dry cell is becoming popular in power supplies to electronic calculators because
- A. it has standard shape
- B. it is dry
- C. it is rechargeable
- D. it is easily manufactured
- Correct Answer: Option C
The composition of a secondary cell is
- A. zinc, copper and dilute sulphuric acid
- B. zinc, carbon and dilute sulphuric acid
- C. lead, lead peroxide and dilute sulphuric acid
- D. zinc, copper dilute boric acid
- Correct Answer: Option C
One advantage of a secondary cell is that it
- A. can be recharged
- B. can be used for portable equipment
- C. it is compact, easy to carry
- D. cannot be recharged
- Correct Answer: Option A
Which of the following acts as depolarizer in dry cell?
- A. manganese dioxide
- B. zinc chloride
- C. ammonium chloride
- D. carbon powder
- Correct Answer: Option A
The function of the depolarizer in carbon zinc cell is that
- A. it converts the produced hydrogen into water
- B. it prevents the fast chemical action on the zinc container
- C. it synthesizes the decomposed electrolyte
- D. it absorbs the oxygen produced in the cell
- Correct Answer: Option A
Cells are connected in series to
- A. decrease the voltage output
- B. increase the voltage output
- C. decrease the internal resistance
- D. increase the current capacity
- Correct Answer: Option B
Cells are connected in parallel to
- A. increases the internal resistance
- B. decrease the current capacity
- C. increase the current capacity
- D. increase the voltage output
- Correct Answer: Option C
When n cells, each of emf E volts, and internal resistance r ohms are connected in parallel, the strength of the current is given by
- A. E/(R r/n)
- B. nE/(r R)
- C. E/(n Rr)
- D. E/(R n/r)
- Correct Answer: Option A
When n cells, each of emf E volts, and internal resistance r ohms are connected in series, the current i through an external resistance R ohms is given by
- A. i = E/(R r/n)
- B. i = E/(R n)
- C. i = nE/(R nr)
- D. i = E/(r nR)
- Correct Answer: Option C